1/2y^2+25/18=25/9y

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Solution for 1/2y^2+25/18=25/9y equation:


y in (-oo:+oo)

(1/2)*y^2+25/18 = (25/9)*y // - (25/9)*y

(1/2)*y^2-((25/9)*y)+25/18 = 0

(1/2)*y^2+(-25/9)*y+25/18 = 0

1/2*y^2-25/9*y+25/18 = 0

DELTA = (-25/9)^2-(1/2*25/18*4)

DELTA = 400/81

DELTA > 0

y = ((400/81)^(1/2)+25/9)/(1/2*2) or y = (25/9-(400/81)^(1/2))/(1/2*2)

y = 5 or y = 5/9

y in { 5/9, 5 }

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